1) The derivative as a “slope sensor” on a graph
When you look at a graph of y=f(x), the derivative f'(x) tells you what the graph is doing right there: whether it is rising or falling, and how steeply. This chapter focuses on reading that information directly from shapes, and on estimating it from data tables.
Sign of f'(x): increasing vs. decreasing
f'(x) > 0: the graph offis increasing (rising as you move right).f'(x) < 0: the graph offis decreasing (falling as you move right).f'(x) = 0: the tangent is horizontal. This often happens at local maxima/minima, but can also happen at “flat” points where the function keeps increasing or decreasing.
Geometrically, the sign is about the direction of the tangent line. A tangent that tilts upward to the right corresponds to positive slope; downward corresponds to negative slope.
Magnitude |f'(x)|: steepness
- Large
|f'(x)|: very steep graph (rapid change infper unit ofx). - Small
|f'(x)|: nearly flat graph (slow change). |f'(x)|near 0: almost horizontal tangent.
Two points can both have positive derivative, but one can be much steeper: for example, a tangent slope of +5 is steeper than +0.5.
2) Where derivatives fail: corners, cusps, and vertical tangents
Some shapes prevent a single well-defined tangent slope at a point. On a graph, these are often visible as “sharp” or “too steep” features.
Corners (sharp turns)
At a corner, the left-hand slope and right-hand slope are different. The graph has a pointy change in direction, so there is no single tangent line that matches both sides.
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- Graph clue: looks like two line segments meeting with different slopes.
- Derivative clue:
f'(x)does not exist at the corner.
Cusps (pointed tips)
A cusp is sharper than a corner: slopes may blow up in magnitude with opposite signs as you approach the point.
- Graph clue: a pointed “needle” tip.
- Derivative clue:
f'(x)does not exist at the cusp.
Vertical tangents
Sometimes the curve becomes so steep that the tangent line is vertical. A vertical line has undefined slope, so the derivative is not a finite number there.
- Graph clue: the curve looks nearly vertical at a point.
- Derivative clue:
f'(x)may be undefined or can be thought of as “infinite slope” (not a real-number derivative).
Quick classification task
For each feature below, decide whether f'(a) exists as a real number.
- A smooth rounded peak (like the top of a hill).
- A V-shaped bottom.
- A smooth curve that becomes vertical at one point.
Write one sentence justifying each answer using “single tangent slope” language.
3) Connecting f and f': key features to match
A powerful skill is translating between the graph of a function and the graph of its derivative. You do not need exact formulas; you focus on structure.
A checklist for sketching f'(x) from a graph of f(x)
- Step 1: Mark where
fhas horizontal tangents. These are candidates forf'(x)=0(zeros of the derivative). - Step 2: Determine where
fis increasing/decreasing. Increasing intervals becomef'(x)>0; decreasing intervals becomef'(x)<0. - Step 3: Compare steepness. Where
fis steep,|f'|should be large; wherefis flat,|f'|should be small. - Step 4: Identify nondifferentiable points. Corners/cusps/vertical tangents in
fbecome points wheref'is undefined (often shown as breaks or open circles in a sketch). - Step 5: Track how slopes change. If the slope of
fis increasing as you move right, thenf'is increasing; if slopes are decreasing, thenf'is decreasing.
Interpreting “slopes increasing or decreasing” (shape of f')
Think of walking along the curve from left to right and watching the tangent slope value.
- If tangent slopes go from
-3to-1to0to2, thenf'(x)is increasing on that interval. - If tangent slopes go from
4to2to1to0, thenf'(x)is decreasing on that interval.
This is a “graph-of-the-slope” viewpoint: f'(x) records the slope values you would write down at each x.
4) Guided sketching problems: from f to f'
Problem A: Smooth hill then valley
Suppose f(x) is smooth and has: a local maximum at x=-2, then decreases until a local minimum at x=1, then increases after that. The graph is steepest around x=0 and flatter near the max/min.
Task: Sketch a plausible f'(x).
- Step 1 (zeros): Put
f'(x)=0atx=-2andx=1. - Step 2 (sign): Since
fincreases before-2, setf'(x)>0forx<-2. Sincefdecreases between-2and1, setf'(x)<0on(-2,1). Sincefincreases after1, setf'(x)>0forx>1. - Step 3 (magnitude): Make
f'(x)most negative nearx=0(steepest downward slope), and closer to 0 nearx=-2andx=1(flatter). - Step 4 (shape): Draw a curve for
f'that crosses the x-axis at-2and1, dips to a minimum near0, and rises afterward.
Short explanation to write: “f' is positive where f rises, negative where f falls, and zero at horizontal tangents; its magnitude reflects steepness.”
Problem B: Corner point
Suppose f(x) is decreasing linearly for x<0 with slope -2, then increasing linearly for x>0 with slope +3, meeting at a sharp corner at x=0.
Task: Sketch f'(x) and describe what happens at x=0.
- For
x<0,f'(x)=-2(a horizontal line at-2). - For
x>0,f'(x)=3(a horizontal line at3). - At
x=0,f'(0)does not exist (jump in slope from-2to3).
Short explanation to write: “A corner has two different one-sided slopes, so there is no single derivative value at the corner.”
Problem C: Vertical tangent
Suppose f(x) is smooth except at x=2, where the curve becomes vertical (the graph looks like it shoots straight up as it passes through x=2).
Task: Describe what you expect for f'(x) near x=2.
- As
xapproaches2, the slopes become extremely large in magnitude. - The derivative at
x=2is not a finite real number, sof'(2)is undefined in the usual sense. - A sketch of
f'would show values growing without bound (or a break) nearx=2.
5) Going the other way: sketching f from a graph of f'
If you are given f'(x), you can reconstruct the shape of f (up to a vertical shift) by interpreting derivative information.
A checklist for sketching f from f'
- Step 1: Find where
f'(x)=0. These are points wherefhas horizontal tangents. - Step 2: Use the sign of
f'. Iff'>0,fincreases; iff'<0,fdecreases. - Step 3: Use the size of
f'. Large positivef'meansfrises steeply; smallf'near 0 meansfis nearly flat. - Step 4: Look for changes in
f'. Iff'is increasing, the slopes offare getting larger (the graph offis “bending upward” in slope). Iff'is decreasing, slopes are getting smaller.
Problem D: Derivative sign chart to function shape
You are told that:
f'(x)>0on(-∞,-1)f'(x)=0atx=-1f'(x)<0on(-1,2)f'(x)=0atx=2f'(x)>0on(2,∞)
Task: Sketch a plausible f(x) and label what happens at x=-1 and x=2.
- Since
f'changes from positive to negative at-1,fhas a local maximum atx=-1. - Since
f'changes from negative to positive at2,fhas a local minimum atx=2. - Between them,
fdecreases; outside them,fincreases.
Short explanation to write: “Where f' is positive the function rises; where negative it falls; sign changes at zeros indicate turning points.”
6) Estimating derivatives from tables (numerical slopes)
When you have data rather than a formula, you estimate f'(x) using average rates of change over small intervals. The basic tool is the difference quotient computed from nearby table values.
Average rate over a small interval
Given values (x, f(x)) and (x+h, f(x+h)), the average rate of change is:
average rate from x to x+h = [f(x+h) - f(x)] / hIf h is small and the data are smooth, this can approximate f'(x).
Forward, backward, and central estimates
- Forward difference:
[f(x+h)-f(x)]/h - Backward difference:
[f(x)-f(x-h)]/h - Central difference:
[f(x+h)-f(x-h)]/(2h)(often more accurate when data are smooth and evenly spaced)
Worked table example (step-by-step)
Suppose you have the table:
| x | f(x) |
|---|---|
| 1.9 | 3.61 |
| 2.0 | 4.00 |
| 2.1 | 4.41 |
Estimate f'(2.0) using different methods.
- Forward difference (h=0.1):
[f(2.1)-f(2.0)]/0.1 = (4.41-4.00)/0.1 = 0.41/0.1 = 4.1 - Backward difference (h=0.1):
[f(2.0)-f(1.9)]/0.1 = (4.00-3.61)/0.1 = 0.39/0.1 = 3.9 - Central difference (h=0.1):
[f(2.1)-f(1.9)]/0.2 = (4.41-3.61)/0.2 = 0.80/0.2 = 4.0
Interpretation: the slope near x=2 is about 4. The forward and backward estimates differ slightly because they sample different sides of the point.
Sensitivity to step size h
Choosing h is a tradeoff:
- If
his too large, the average rate may miss local behavior (it “smears” the slope over a wide interval). - If
his very small, measurement noise or rounding can dominate the subtractionf(x+h)-f(x), making the estimate unstable.
Mini-task: If a sensor reports f(x) rounded to the nearest 0.01, explain in 1–2 sentences why using h=0.001 could produce unreliable derivative estimates.
Noisy data: what to do
With noise, derivative estimates can fluctuate wildly because differentiation amplifies small wiggles in the data.
- Use central differences when possible (they average information from both sides).
- Use a slightly larger
hto reduce noise sensitivity, while staying local enough to reflect the shape. - Look for trends (sign and relative magnitude) rather than expecting a perfectly smooth derivative curve.
7) Guided interpretation problems (short written explanations)
Problem E: Reading sign and zeros from a graph description
A graph of f is smooth. It rises from x=-4 to x=-1, is flat at x=-1, then falls until x=3, is flat again at x=3, then rises after 3.
- Question 1: On which intervals is
f'(x)positive? negative? - Question 2: Where does
f'(x)=0? - Write-up (2–3 sentences): Explain how you know using increasing/decreasing language.
Problem F: Matching steepness
On (0,1) the graph of f rises gently; on (1,2) it rises very steeply; on (2,3) it still rises but begins to flatten.
- Task: Describe how
f'(x)compares across these intervals (small positive vs. large positive, increasing vs. decreasing). - Write-up (1–2 sentences): Use the phrase “magnitude of the derivative” correctly.
Problem G: Detecting nondifferentiability from a sketch
You see a curve that is smooth everywhere except at x=5, where it has a sharp corner.
- Question: What happens to
f'(5)? - Write-up (1–2 sentences): Mention one-sided slopes and why they prevent a single tangent slope.
Problem H: Estimating f'(x) from a data table and commenting on reliability
Given:
| x | f(x) |
|---|---|
| 10 | 50.2 |
| 11 | 50.9 |
| 12 | 51.1 |
- Task 1: Estimate
f'(11)using a central difference withh=1. - Task 2: Estimate
f'(11)using a forward difference withh=1. - Task 3: In 2–3 sentences, discuss why the two estimates differ and what that suggests about the local behavior or noise.