1) Plot vertices from coordinates and label sides
When analyzing a triangle on the coordinate plane, start by naming the vertices and connecting them in order. Use consistent labels so your calculations match your diagram.
Example A: Build triangle ABC
Let A(-1, 1), B(5, 1), and C(2, 5).
- Plot points
A,B,C. - Draw segments
AB,BC, andCA. - Label the sides:
ABis oppositeC,BCis oppositeA,CAis oppositeB.
To keep work organized, create a quick reference table of the three sides you will analyze.
| Side | Endpoints |
|---|---|
AB | A(-1,1) to B(5,1) |
BC | B(5,1) to C(2,5) |
CA | C(2,5) to A(-1,1) |
2) Compute side lengths to classify the triangle
To classify a triangle by side lengths, compute the three side lengths and compare them.
- Scalene: all three side lengths are different.
- Isosceles: two side lengths are equal.
- Equilateral: all three side lengths are equal (this can happen on the coordinate plane, though it may involve non-integer lengths).
Tip: compare squared lengths to avoid radicals
Because distance calculations often produce square roots, it is efficient to compare squared side lengths. If AB^2 = AC^2, then AB = AC without needing to simplify square roots.
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Example A continued: classify triangle ABC by side lengths
Compute squared lengths:
AB^2 = (5 - (-1))^2 + (1 - 1)^2 = 6^2 + 0^2 = 36
BC^2 = (2 - 5)^2 + (5 - 1)^2 = (-3)^2 + 4^2 = 9 + 16 = 25
CA^2 = (-1 - 2)^2 + (1 - 5)^2 = (-3)^2 + (-4)^2 = 9 + 16 = 25Since BC^2 = CA^2 = 25, the triangle has two equal sides (BC = CA), so it is isosceles. Because AB^2 is different, it is not equilateral.
Example B: a scalene triangle
Let P(0,0), Q(4,1), R(1,5). Compute squared lengths:
PQ^2 = (4-0)^2 + (1-0)^2 = 16 + 1 = 17
QR^2 = (1-4)^2 + (5-1)^2 = 9 + 16 = 25
RP^2 = (0-1)^2 + (0-5)^2 = 1 + 25 = 26All three squared lengths are different, so triangle PQR is scalene.
Example C: an equilateral triangle (when applicable)
Equilateral triangles can be formed using coordinates, though the coordinates may not all be integers. For instance, take A(0,0), B(2,0), and C(1, √3).
AB^2 = (2-0)^2 + (0-0)^2 = 4
AC^2 = (1-0)^2 + (√3-0)^2 = 1 + 3 = 4
BC^2 = (1-2)^2 + (√3-0)^2 = 1 + 3 = 4All three squared lengths match, so the triangle is equilateral.
3) Use slopes to identify right angles and parallel sides
Slopes help you verify angle relationships without measuring angles directly.
Right angles via perpendicular slopes
Two non-vertical lines are perpendicular if their slopes are negative reciprocals: if m1 · m2 = -1. Special cases:
- A horizontal line (slope
0) is perpendicular to a vertical line (undefined slope). - If one segment is vertical, check whether the other is horizontal to confirm perpendicularity.
Example D: verify a right triangle using slopes
Let A(1,1), B(1,6), C(5,1).
ABis vertical (samex-coordinate), so its slope is undefined.ACis horizontal (samey-coordinate), so its slope is0.
A vertical segment is perpendicular to a horizontal segment, so angle A is a right angle and triangle ABC is a right triangle.
Parallel sides in related constructions
In triangles, you may create or analyze additional segments (like midsegments) where parallelism matters. Two non-vertical segments are parallel if their slopes are equal. Two vertical segments are parallel to each other as well.
Example E: midsegment parallel to a side (uses midpoint + slope)
Let triangle ABC have A(0,0), B(6,0), C(2,4). Find the midpoints of AB and AC, then compare slopes.
M = midpoint of AB = ((0+6)/2, (0+0)/2) = (3,0)
N = midpoint of AC = ((0+2)/2, (0+4)/2) = (1,2)Compute slopes:
slope(MN) = (2-0)/(1-3) = 2/(-2) = -1
slope(BC) = (4-0)/(2-6) = 4/(-4) = -1Since the slopes match, MN is parallel to BC. This is a coordinate-based verification of a common triangle construction: the segment joining midpoints of two sides is parallel to the third side.
4) Validation tasks: calculate, then confirm by accurate graphing
Validation means you do the algebraic checks first (distance and slope), then you graph carefully to see whether the picture matches your results. The graph is a confirmation, not a substitute for calculation.
Task 1: Determine whether a triangle is right
Given A(-2,1), B(3,4), C(1,-1).
Step 1: compute slopes of two sides that meet at a vertex (try vertex B using BA and BC).
m_BA = (1-4)/(-2-3) = (-3)/(-5) = 3/5
m_BC = (-1-4)/(1-3) = (-5)/(-2) = 5/2Step 2: check perpendicular condition
m_BA · m_BC = (3/5) · (5/2) = 3/2 ≠ -1So the angle at B is not right. Check another vertex (for example, slopes AB and AC at A).
m_AB = (4-1)/(3-(-2)) = 3/5
m_AC = (-1-1)/(1-(-2)) = (-2)/3 = -2/3
m_AB · m_AC = (3/5) · (-2/3) = -2/5 ≠ -1Not right at A. Check at C:
m_CA = (1-(-1))/(-2-1) = 2/(-3) = -2/3
m_CB = (4-(-1))/(3-1) = 5/2
m_CA · m_CB = (-2/3) · (5/2) = -5/3 ≠ -1Result: triangle ABC is not a right triangle.
Step 3: confirm by graphing
- Plot
A,B,Caccurately. - Draw the sides and visually inspect angles; none should appear to be exactly 90°.
- If your drawing seems to show a right angle, re-check plotting accuracy and slope arithmetic.
Task 2: Determine whether a triangle is isosceles
Given P(-1,2), Q(3,2), R(1,6).
Step 1: compute squared side lengths
PQ^2 = (3-(-1))^2 + (2-2)^2 = 4^2 + 0^2 = 16
PR^2 = (1-(-1))^2 + (6-2)^2 = 2^2 + 4^2 = 4 + 16 = 20
QR^2 = (1-3)^2 + (6-2)^2 = (-2)^2 + 4^2 = 4 + 16 = 20Step 2: compare
PR^2 = QR^2, so PR = QR. Triangle PQR is isosceles with equal sides meeting at R (so R is the vertex of the equal sides, and PQ is the base).
Step 3: confirm by graphing
- Plot
PandQon the horizontal liney=2, then plotRabove them. - Draw segments
PRandQR; they should look symmetric around the vertical line through the midpoint ofPQ.
Task 3: Combine midpoint and slope to validate a construction
Given A(0,1), B(8,3), C(2,7). Let M be the midpoint of AB and N the midpoint of AC. Verify that MN is parallel to BC.
Step 1: midpoints
M = ((0+8)/2, (1+3)/2) = (4,2)
N = ((0+2)/2, (1+7)/2) = (1,4)Step 2: slopes
slope(MN) = (4-2)/(1-4) = 2/(-3) = -2/3
slope(BC) = (7-3)/(2-8) = 4/(-6) = -2/3Result: slopes match, so MN is parallel to BC.
Step 3: confirm by graphing
- Plot
A,B,C, then plotMandN. - Draw
BCandMN; they should have the same tilt and never meet.